Engineering
Physics
Contact Force
Relative Motion
Newtons Second Law of Motion
Question

An insect of mass m is initially at one end of a stick of length L and mass M, which rests on a smooth floor. The coefficient of friction between the insect and the stick is k. The minimum time in which the insect can reach the other end of the stick is t. Then t2 is equal to

2Lm/kgM

2Lm/kg(M+m)

2L/kg

2LM/kg(M + m)

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Solution
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Fm = mµg  ⟹  am = µg
FM = µmg

aM=μmgM

arel =aM+am=μg1+mM

L=12arelt2

t2=2LMμg(M+m).