Engineering
Physics
Thermodynamics
Question
0.056 kg of Nitrogen is enclosed in a vessel at a temperature of 127°C. The amount of heat required to double the speed of its molecules is __________ k cal.
(Take R = 2 cal mole–1 K–1)
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Solution
M
N2 = 28
V = C
T2 = 4T1
ΔQ = ?
ΔQ = nCvΔT
= 5 × 2 × 3 × 400
= 12000 cal
= 12 kcal
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