Foundation
Chemistry Foundation
Nuclear Chemistry
Question

1 milligram radium has 2.68 × 1018 atoms. Its half life period is 1620 years. Number of  radium atoms that disintegrate from 1 millgram of pure radium in 3240 years are -

4.02 × 1022

2.01 × 1018

4.02 × 1018    

2.01 × 1022

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Solution

The half-life is the time for half the atoms to decay. In 3240 years (2 half-lives: 3240/1620=2), the number of undecayed atoms left is given by the decay formula: N=N0(12)tT1/2. Substituting t=3240 and T1/2=1620, we get N=2.68×1018(12)2=6.7×1017. The number of atoms disintegrated is the initial minus the remaining: 2.68×1018-6.7×1017=2.01×1018.

Final Answer:

2.01 × 1018