10 L sample of an ideal gas is expanded reversibly and isothermally at 300K from initial pressure of 10 atm to final pressure of 1 atm. The heat absorbed by gas during the process is approximately

Engineering

Chemistry

First Law and Various Process

Question

23 kJ

50 kJ

15 kJ

32 kJ

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W = – nRT ln $\frac{V_{2}}{V_{1}}$ = – P₁V₁ ln $\frac{V_{2}}{V_{1}}$ L atm
   = – 100 ln 10
   = – 2.303 × 100 × 101.355 ≈ –23 kJ
   = q ≈ + 23 kJ