112.0 mL of NO2 at STP was liquefied, the density of the liquid being 1.15 g mL–1. Calculate the volume and the number of molecules in the liquid NO2.

Engineering

Chemistry

Mole and Its Calculation

Question

112.0 mL of NO₂ at STP was liquefied, the density of the liquid being 1.15 g mL^–1. Calculate the volume and the number of molecules in the liquid NO₂.

0.20 mL and 3.01 × 10²¹

0.40 mL and 6.02 × 10²¹

0.10 mL and 3.01 × 10²²

0.20 mL and 6.02 × 10²³

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$Mole of {NO}_{2} = \frac{112}{22400} = 5 \times 10^{- 3};$ Mass of NO₂ = 5 × 10^–3 × 46 = 0.23 g

$Volume of {NO}_{2} = \frac{Mass}{Density} = \frac{0.23}{1.15} = 0.2 ml;$ Number of molecule = 5 × 10^–3 × 6.0²³ × 10²³ = 3.1 × 10²¹.