Engineering
Physics
SI Units
Mechanical Power
Question
A 1 h.p. electric motor operates a pump continuously. The work performed by the motor in one day is
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Solution
Solution: Mathematically, 1 h.p.=746 W
Also, 1 kW = 1000 W
So, 1h.p. = 0.746 kW
Work done by the motor in one day or 24 hrs is given by, E = P × t
where, E denotes electrical energy,
P denotes the power in kilowatt and t denotes the time in hours Substituting the values in the above equation we get,
E = 0.746 kW × 24
E = 18 kWh
Hence, the correct option is (A).