Engineering
Physics
Newtons Second Law of Motion
Center of Mass
Summation of Vectors
Question
A 640 - N hunter gets a rope around a 3200 N polar bear. They are stationary, 30m apart, on frictionless level ice. When the hunter pulls the polar bear to meet him, the polar bear will move:
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Solution
m1s1 + m2s2 = 0
640 × s1 + 3200 s2 = 0
s2 – s1 = 30
6s2 – 30 = 0
s2 = 5 m.