Engineering
Physics
Newtons Second Law of Motion
Question

A block of mass m slides on the wooden wedge, which in turn slides backwards on the horizontal surface. The acceleration of the block with respect to the wedge is: Given m = 8 kg, M = 16 kg Assume all the surfaces shown in the figure to be frictionless.

43g

35g

65g

23g

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Solution

N cos 60º = Ma1 = 16 a1

⇒         N = 32 a1

to incline

N=8gcos30º8a1sin30º32a1=443g4a1

       a2=39g

Alone incline

8 g sin 30° + 8a1 cos 30° = ma2 = 8a2

a2=g×12+39g.32=2g3

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