Foundation
Mathematics Foundation
Time Speed Distance
Question
A dog at point A goes in pursuit of a fox 40 m away. The dog takes a leap of 2 m against 1 m long leaps of the fox. If the dog makes two leaps to the fox’s three, at what distance from A will the dog catch up with the fox?
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Solution
Two of the dog’s leaps cover 4 m.
Three of the fox’s leaps cover 3 m
Each time the dogs runs 4 m.
Then distance = 4m – 3m = 1m
The initial distance between them is 40m, hence the dog will catch up the fox when it covers 4 × 40 = 160 m
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