A graph between the square of the velocity of a particle and the distance s moved by the particle is shown in the figure. The acceleration of the particle in kilometer per hour square is:

Engineering

Physics

Acceleration

Straight Line Motion

Question

A graph between the square of the velocity of a particle and the distance s moved by the particle is shown in the figure. The acceleration of the particle in kilometer per hour square is:

2250

– 2250

– 225

225

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$∵ V_{f}^{2} = V_{i}^{2} + 2 as$
$a = \frac{V_{f}^{2} - V_{i}^{2}}{2 s} = \frac{900 - 3600}{2 \times 0 .6} = \frac{- 2700}{2 \times 0 .6} = \frac{- 27000}{12} = - 2250$