Engineering
Physics
Newtons Second Law of Motion
AC Circuit Analysis
LCR and Resonance in AC Circuit
Question

A inductor of inductive reactance 100 Ω, a capacitor of capacitive reactance 50 Ω and resistor of resistance R Ω are connected in a series as shown in figure. All voltmeters and ammeter connected in circuit are ideal. The reading of voltmeter V1 and V2 is 400 Volt and 200 Volt respectively and reading of ammeter is 4 amp. The reading of voltmeter V3 and resistance of resistor are

100(221)V,50Ω

100(221),100Ω

100 V, 100 Ω

200 V, 50 Ω

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Solution
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i=VZ

4=2002(50)2+R2

R = 50 Ω
VR = i × R = 200 V