A metal chloride contains 55.0% of chlorine by weight. 100 mL vapours of the metal chloride at STP weigh 0.57g. The molecular formula of the metal chloride is (Given: Atomic mass of chlorine is 35.5u)

Engineering

Chemistry

Nucleophilic Substitution

Question

MCl₃

MCl₂

MCl

MCl₄

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number of mole of metal chloride = $\frac{100}{22400}$

100 ml of metal chloride gives = 0.57g of Cl₂ at STP

so 22400 ml = 1 mole of metal chloride gives = $\frac{0.57}{100} \times 22400 g$ of Cl₂ at STP = 127.68 gm

Mass of chlorine = 55% by Mass of metal chloride = $\frac{55}{100} \times 127.68 = 70.224$

Number of moles of chlorine in metal chloride = $\frac{70.224}{35.5} = 1.978 \approx 2$

Formula of metal chloride : MCl₂

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