Engineering
Physics
Conservation of Angular Momentum
Question

A particle performs uniform circular motion with an angular momentum L. If the frequency of particle’s motion is doubled and its kinetic energy is halved, the angular momentum becomes

L/2

2L

L/4

4L

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Solution
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I1ω1I2ω2 = L1L2
ω2 = 2ω1
12 I2ω22 = 12(12I1ω12)    ⟹ I2I18
⟹   L2L14

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