A person travels along straight road for the first half time with a velocity v1 and the second half time with a velocity v2 . Then the mean velocity v is given by :

Foundation

Physics Foundation

Types of Motion Distance and Displacement

Question

A person travels along straight road for the first half time with a velocity v₁ and the second half time with a velocity v₂ . Then the mean velocity v is given by :

$\frac{2}{v} = \frac{1}{v_{1}} \times \frac{1}{v_{2}}$

$V = \sqrt{\frac{V_{2}}{V_{1}}}$

$v = \sqrt{(v_{1} v_{2})}$

$v = \frac{v_{1} + v_{2}}{2}$

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Mean velocity = $\frac{Total displacement}{total time}$

$V_{avg} = \frac{v_{1} \times \frac{t}{2} + v_{2} \times \frac{t}{2}}{\frac{t}{2} + \frac{t}{2}} = \frac{(v_{1} + v_{2}) \frac{t}{2}}{\frac{t}{2} (2)} = \frac{v_{1} + v_{2}}{2}$