A point charge q is placed on the axis of a fixed ring of radius R so that the point charge is at a distance 3R/4 from the center of the ring. The electric flux through the ring due to the charge q is . Fill 10 n.

Engineering

Physics

Electric Flux and Gauss Law and its Applications

Question

A point charge q is placed on the axis of a fixed ring of radius R so that the point charge is at a distance 3R/4 from the center of the ring. The electric flux through the ring due to the charge q is $\frac{nq}{\in_{0}}$ . Fill 10 n.

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$\frac{ϕ}{ϕ_{T}} = \frac{Ω}{4 π} = \frac{2 π}{4 π} (1 - \cos θ)$

$tanθ = \frac{4}{3} ϕ = \frac{q}{2 \in_{0}} (1 - \frac{3}{5})$

θ = 53º $\frac{q}{5 \in_{0}}$

10n = 2