A pole is vertically submerged in swimming pool, such that it gives a length of shadow 2.15 m within water when sunlight is incident at an angle of 30° with the surface of water. If swimming pool is filled to a height of 1.5 m, then the height of the pole above the water surface in centimetres is (nw = 4/3).
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x = 2.15
x1 + x2 = 2.15 …..(1)
tan60° = =
x1 =
Snell’s law
1 × sin60º = 4/3 × sin r
…(2)
Tan r =
X2 = ...(3)
From equation (1) & (3)
h = 0.5 m = 50 cm