Engineering
Physics
Physical Quantities
Acceleration
Stress Strain and Hookes Law New
Question

A rubber cord of length 40 cm and area of cross section 4 x 10−6 m2 is extended by 10 cm. If the energy gained is 20 joule , young's modulus of rubber is

108Nm−2

2 × 108Nm−2

4 × 108Nm−2

1.5 × 106Nm−2

JEE Advance
College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Solution
Verified BY
Verified by Zigyan

Energy=AY2L2 
20=4×106×Y×(10100)22×40100 
Y=20×2×404×106×(10100)2×100 

= 4 × 108 N/m2