A shot putter with a mass of 80 kg pushes the iron ball of mass of 6 kg from a standing position, accelerating it uniformly from rest at an angle of 45° with the horizontal during a time interval of 0.1 seconds. The ball leaves his hand when it is 2 m high above the level ground and hits the ground 2 seconds later.
Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.
Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA
The minimum value of the static coefficient of friction if the shot putter does not slip during the shot is closest to :
Fy – 60 = 90 × 6 ⇒ Fy = 540 + 60 = 600 N
Fx = 6 × 90 = 540 N
N = Fy + Mg = 600 + 800 = 1400 N
mN = Fx ⇒ m = 540/1400 = 0.38
Please subscribe our Youtube channel to unlock this solution.
The acceleration of the ball in shot putter's hand
Please subscribe our Youtube channel to unlock this solution.
The horizontal distance between the point of release and the point where the ball hits the ground
Please subscribe our Youtube channel to unlock this solution.