A steel wire (Y = 200 GPa) of cross-sectional area = 1 mm2 is stretched by a force = 1000 N. The percentage increases in length of the wire is

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Stress Strain and Hookes Law New

Question

A steel wire (Y = 200 GPa) of cross-sectional area = 1 mm² is stretched by a force = 1000 N. The percentage increases in length of the wire is

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Percentage increase = × 100% = strain × 100%
= $\frac{stress}{y}$ × 100% = $\frac{1000 N}{{(1 mm)}^{2}}$ × 100% = 0.5%.