A very small circular loop of area 5 × 10–4 m2 and resistance 2 ohm is initially concentric and coplanar with a stationary loop of radius 0.1 m. If one ampere constant current is passed through the bigger loop and the smaller loop is rotated about its diameter with constant angular velocity ω. The current induced (in ampere) in the smaller loop will be :

Engineering

Physics

Faraday

Magnetic Flux and Faraday Law and Lenz Law

Magnetic Field

Question

A very small circular loop of area 5 × 10^–4 m² and resistance 2 ohm is initially concentric and coplanar with a stationary loop of radius 0.1 m. If one ampere constant current is passed through the bigger loop and the smaller loop is rotated about its diameter with constant angular velocity ω. The current induced (in ampere) in the smaller loop will be :

πω × 10^–9 sinωt

$\frac{πω}{2}$ ×10^–9 sinωt

$\frac{πω}{2}$ × 10^–9 cosωt

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

E = π × 10^–9 ωsinωt
Also E = i × 2.
⇒ i = $\frac{πω}{2}$ × 10^–9 sin ωt.