Engineering
Chemistry
Integrated Rate Law
Question

Consider the two different first order reaction given below

A + B → C (Reaction 1)

P → Q (Reaction 2)

The ratio of the half life of reaction 1 : Reaction 2 is 5 : 2. If t1 and t2 represent the time taken to complete 2/3rd and 4/5th of Reaction 1 and Reaction 2, respectively, then the value of the ratio t1 : t2 is ____________ × 10–1 (nearest integer).

[Given : log10(3) = 0.477 and log10(5) = 0.699]

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Solution

t12It122II=K2K1=52

K1t1=ℓn1123=ℓn3

K2t2=ℓn1145=ℓn5

K1t1K2t2=0.4770.699

t1t2=0.4770.699×52=1.7=17×101