Engineering
Chemistry
Types of Redox Reaction
Equivalent Mass and n factor
Question

Find the oxidation number of Pt in [PtCl6]2− ion.

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Solution
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Let oxidation number of Pt be x.

We know that Ox. no. of Cl = −1.

So, Ox. no. Pt + 6 (Ox.no.Cl) = −2

x + 6(−1) = −2

or x − 6 = −2

or x = +6 − 2 = +4

The oxidation number of Pt in [Pt(Cl)6]2− ion is +4 .

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