Find the oxidation number of Pt in [PtCl6]2− ion.
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Let oxidation number of Pt be x.
We know that Ox. no. of Cl = −1.
So, Ox. no. Pt + 6 (Ox.no.Cl) = −2
x + 6(−1) = −2
or x − 6 = −2
or x = +6 − 2 = +4
The oxidation number of Pt in [Pt(Cl)6]2− ion is +4 .
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