Engineering
Chemistry
Application of Electronegativity
Question

For AB bond if % ionic character is plotted against electronegativity difference (|XA – XB|), the shape of the curve would look like:

B

A

D

C

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Solution

% ionic character = 16 | EN | + 3.5 | EN |2
If EN increases then % I.C. increases
if % ionic character = 50 % then EN ≈ 2.1 the shape of the curve would look like "C".