For an ideal gas graph is shown for three processes. Processes 1, 2 and 3 are respectively.

Engineering

Physics

Thermodynamics

Question

Isochoric, adiabatic, isobaric

Isobaric, adiabatic, isochoric

Isochoric, isobaric, adiabatic

Adiabatic, isobaric, isochoric

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Isochoric process dv = 0

W = 0

Isobaric : W = PΔV = nRΔT

Adiabatic : W = $\frac{nR (T_{i} - T_{f})}{r - 1}$

$| W | = \frac{nRΔT}{r - 1}$ ⇒ 0 < r – 1 < 1