Engineering
Chemistry
Catalysis and Kinetics
Question

For following reactions

A700Kproduct

Acatalyst500Kproduct

it was found that the Ea is decreased by 30 kJ/mol in the presence of catalyst. If the rate remains unchanged, the activation energy for catalysed reaction is (Assumer pre exponential factor is same) :

195 kJ/mol

135 kJ/mol

105 kJ/mol       

75 kJ/mol

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Solution

Kcat = K

AeEa1RT1=AeEa2RT2

Ea1RT1=Ea2RT2Ea1=Ea230

Ea230500=Ea2700

5Ea2 = 7Ea2 – 210

Ea2=2102=105  kJ/mole

Activation energy of the catalysed reaction = 105 – 30 = 75 kJ/mole

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