For the circuit shown in the figure. Find the emf (in mV) of the unknown battery E. The ammeter represented by the symbol A can be considered perfect (i.e. no resistance) and it reads the current in the wire to be 0.5 A in the direction shown.

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For the mesh BCFEB,
⟹ – 8 – 10I – 3 = 0
⟹ I = –1.1A
For the mesh ABCDA,

∴ –12 + 4.4 + I + ε = 0
∴ E = 6.6 V = 6600 mV