From the phase diagram of water and an aqueous solution containing non volatile solute, identify the incorrect option:

Engineering

Chemistry

Raoult Law and Vapour Pressure

Question

$P_{1} = P_{2} e^{- \frac{{ΔH}_{vap}}{R} \frac{[T_{0} - T_{1}]}{T_{0} T_{1}}}$

Order of vapour pressure (P₀, P₁, P₂) are P₀> P₁> P₂.

At temperature T₀ , vapour pressure of solid and vapour pressure of liquid will be same.

$P_{0} = P_{2} e^{- \frac{{ΔH}_{fusion}}{R} \frac{[T_{0} - T_{1}]}{T_{0} T_{1}}}$

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(A) Temperature T₀ , represent tripple point of solvent where

are in equilibrium hence vapour pressure of solid and vapour pressure of liquid will be same.
(B) Figure showing P₀ > P₁ > P₂
(C) Line corresponding to P₀ and P₂ vapour pressure

$Solid ⇌_{}^{} vapour$
Hence ln $\frac{P_{2}}{P_{0}} = \frac{{ΔH}_{sub}}{R} [\frac{1}{T_{0}} - \frac{1}{T_{1}}]$
(D) Line corresponding to P₁ and P₂ vapour pressure
$Liquid ⇌_{}^{} vapour$
Hence ln $\frac{P_{2}}{P_{1}} = \frac{{ΔH}_{vap}}{R} [\frac{1}{T_{0}} - \frac{1}{T_{1}}]$