How many oxygen atoms will be present in 88 g of CO2?

Foundation

Chemistry Foundation

Atoms and Molecules

Mole Concept and Calculation

Question

How many oxygen atoms will be present in 88 g of CO₂?

24.08 × 10²³

6.023 × 10²³

44 × 10²³

22 × 10²⁴

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1 mol of CO₂= 12 + 32 = 44 g

Number of oxygen atoms in 1 molecule of CO₂= 2

∴ 44 g CO₂ contains 2 mol oxygen

88 g CO₂contains $= \frac{2}{44} \times 88 = 4 mol oxygen$ atoms

as, 1 mol = 6.022 × 10²³atoms

4 mol oxygen = 4 × 6.022 × 10²³ oxygen atoms

= 24.08 × 10²³ oxtgen atoms

Hence, option A is correct.

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