If 20Cr = 20Cr−10, then the value of 18Cr is:
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Given 20Cr = 20Cr−10
We Know nCr = nCn−r
⇒ r + (n − r) = n
⇒ r + r − 10 = 20
⇒ 2r = 30
⇒ r = 15
⇒ 18Cr = 18C15
⇒ 48 × 17
⇒ 816