Engineering
Mathematics
Introduction to Matrix
Algebra of Matrices
Inverse of a Matrix
Question

If A=[334234011], then : A–1 =

A4

A3

A

A2

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Solution
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Given

A=3    3    42    3    40    1    1

A1=1|A|adjA

|A| = 3(– 3 + 4) + 3(2 – 0) + 4(– 2 – 0)

= 3 + 6 – 8

= 1

A1=1112+10234233

=110234233

A3 = A · A · A

=3    3    42    3    40    1    13    3    42    3    40    1    1334234011

A3=110234233=A1