If a rubber ball is taken at the depth of 200 m in a pool its volume decreases by 0.1% If the density of the water is ,1 × 103 kg/m3 and g = 10 m/s2 then the volume elasticity in N/m2 will be

Engineering

Physics

Liquid Pressure

Stress Strain and Hookes Law New

SI Units

Question

If a rubber ball is taken at the depth of 200 m in a pool its volume decreases by 0.1% If the density of the water is ,1 × 10³kg/m³ and g = 10 m/s² then the volume elasticity in N/m² will be

10⁹

20 × 10⁹

10⁸

2 × 10⁸

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$K = \frac{ΔP}{ΔV / V} = \frac{hpg}{ΔV / V} = \frac{200 \times 10^{3} \times 10}{0.1 \times 100} = 2 \times 10^{9}$