Engineering
Chemistry
Enthalpy of Neutralisation and Resonance Energy
Question

If enthalpy of hydrogenation of C6H6(ℓ) into C6H12(ℓ) is –205 kJ & resonance energy of C6H6(ℓ) –152 kJ/mol then enthalpy of hydrogenation of 1,4-cyclohexadiene (ℓ) is 
[Assume ΔHvap of C6H6(ℓ), C6H8(ℓ), C6H12(ℓ) all are equal]

–357 kJ/mol

–535.5 kJ/mol

None

–238 kJ/mol

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Solution

=    ΔHT – ΔHA = – 152
=    ΔHT = – 152 – 205 = – 357

ΔH = + 2 × (–119) = – 238 kJ/mol