Engineering
Chemistry
Kirchoffs Equation
Question

If enthalpy of neutralization of CH3COOH by NaOH is –49.86 kJ/mol then enthalpy of ionzation of CH3COOH is:

None of these

105.7 kJ/mol

5.98 kJ/mol

–5.98 kJ/mol

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Solution
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ΔH = ΔH° – ΔH° (H + OH → H2O )

= – 49.86 – (–55.84) kJ/mole

=  5.98 kJ/mole

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