In a simultaneous throw of two dice what is the probability of getting a doublet ?

Foundation

Mathematics Foundation

Definition of Probability

Question

$\frac{1}{6}$

$\frac{3}{4}$

$\frac{2}{3}$

$\frac{1}{4}$

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Total number of possibilities = $36$
Number of doublet = $6$
Thus, probability = $\frac{6}{36} = \frac{1}{6}$