Given equation of the plan is 

z = 2

Comparing with ax + by + cz = d

a = 0, b = 0, c = 1, d =2

$\sqrt{{\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2}=\sqrt{0^2+0^2+1^2}=1$

Dorection cosines of the normal to the plane are 

$\mathrm{\ell }=\frac{\mathrm{a}}{\sqrt{{\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2}},\mathrm{m}=\frac{\mathrm{b}}{\sqrt{{\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2}},\mathrm{n}=\frac{\mathrm{c}}{\sqrt{{\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2}}$

i = 0, m = 0, n = 1

∴  Direction consine of the normal to the plane are = (0,0,1)

Distance from the original$=\frac{\mathrm{d}}{\sqrt{{\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2}}=2$