In the adjoining figure, the disc of mass M and radius R is in equilibrium. The extension in spring (1) is R/100. The extension is spring (2), and the compression in spring (3), are respectively.

Engineering

Physics

Equilibrium

Newtons Second Law of Motion

Stress Strain and Hookes Law New

Question

In the adjoining figure, the disc of mass M and radius R is in equilibrium. The extension in spring (1) is R/100. The extension is spring (2), and the compression in spring (3), are respectively.

$\frac{3 R}{200}, \frac{R}{150}$

$\frac{R}{100}, \frac{R}{100}$

$\frac{R}{100}, \frac{R}{200}$

$\frac{R}{100}, \frac{R}{150}$

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$\frac{kR}{100}$ × R = 3k × x × $\frac{R}{2}$
x = $\frac{2 R}{300}$ = $\frac{R}{150}$
k × $\frac{R}{100}$ + 3k × $\frac{R}{150}$ = 2kxx'
k × $\frac{3 R}{100}$ = 2k ×x'
x' = $\frac{3 R}{200}$