In the circuit shown in figure, if switch S is closed, the charge that flows through battery is equal to :

Engineering

Physics

Parallel Plate Capacitor

Question

15 μC

zero

7.5 μC

10 μC

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Q₂ – Q₁ = 15 ... (1)
$\frac{Q_{1}}{C_{1}} + \frac{Q_{2}}{C_{2}} = 10$
$\frac{Q_{1}}{3} + \frac{Q_{2}}{3} = 10$
⇒ Q₁ + Q₂ = 30 ... (2)
   Add (1) & (2)
   2Q₂ = 45
   Q₂= $\frac{45}{2}$ μC
   Q₁ = $\frac{15}{2}$ μC

Please subscribe our Youtube channel to unlock this solution.