In the cube of side 'a' shown in the figure, the vector from the central point of the face ABOD to the central point of the face BEFO will be :

Engineering

Physics

Position Vector

Question

$\frac{1}{2} a (\hat{i} - \hat{k})$

$\frac{1}{2} a (\hat{k} - \hat{i})$

$\frac{1}{2} a (\hat{j} - \hat{k})$

$\frac{1}{2} a (\hat{j} - \hat{i})$

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$C o o r d i n a t e o f 2 = (\frac{a}{2}, 0, \frac{a}{2})$

$C o o r d i n a t e o f 1 = (0, \frac{a}{2}, \frac{a}{2})$

${\vec{r}}_{2} - {\vec{r}}_{1} = \frac{a}{2} \hat{j} - \frac{a}{2} \hat{i}$

$Unit vector = \frac{\hat{j} - \hat{i}}{\sqrt{2}}$