Engineering
Physics
Electric Flux and Gauss Law and its Applications
Question

In the figure a very large plane sheet of positive charge is shown. P1 and P2 are two points at distance ℓ and 2ℓ from the charge distribution. If σ is the surface charge density, then the magnitude of electric fields E1 at E2 at P1 and P2 respectively are:

E1 = E2 = σ/ε0

E1 = σ/ε0, E2 = σ/2ε0

E1 = 2σ/ε0, E2 = σ/ε0

E1 = E2 = σ/2ε0

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Solution

Electric field due to a large non-conducting sheet

E=σ2εo and it is uniform width distance from the sheet