In the following arrangement string is light and inextensible. All surfaces are smooth. Treating : a = acceleration of wedge A b = acceleration of block B T = tension in the string N = normal reaction on block B applied by wedge A (A) \frac{4 a}{g} (P) \sqrt{3} (B) \frac{8 T}{mg} (Q) 3 \sqrt{3} (C) \frac{8 N}{mg} (R) 1 (D) \frac{3 b}{a} (S) 3

Engineering

Physics

Newtons First Law of Motion

Question

In the following arrangement string is light and inextensible. All surfaces are smooth. Treating :
a = acceleration of wedge A b = acceleration of block B
T = tension in the string N = normal reaction on block B applied by wedge A

(A) $\frac{4 a}{g}$	(P) $\sqrt{3}$
(B) $\frac{8 T}{mg}$	(Q) $3 \sqrt{3}$
(C) $\frac{8 N}{mg}$	(R) 1
(D) $\frac{3 b}{a}$	(S) 3

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T + N sin 60° – T cos 60° = ma ......... (1)

$b = \sqrt{a^{2} + a^{2} + 2 a^{2} \cos 120 °}$ ......... (2)

mg sin 60 – T = ma (1 – cos 60°) ......... (3)
mg cos 60 – N = ma sin 60° ......... (4)
By eq. (1), (2), (3), (4)

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