In the given triangular sheet, PQ = QR = ℓ and ∠PQR = 90°. If M is the mass of the sheet, then its moment of inertia about PR is

Engineering

Physics

Center of Mass

Moment of Inertia

Calculus

Question

In the given triangular sheet, PQ = QR = ℓ and ∠PQR = 90°. If M is the mass of the sheet, then its moment of inertia about PR is

$\frac{{Mℓ}^{2}}{6}$

$\frac{{Mℓ}^{2}}{3}$

$\frac{{Mℓ}^{2}}{24}$

$\frac{{Mℓ}^{2}}{12}$

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

2I + 2I = $\frac{1}{12}$ × 2M (L² + L²)
I = $\frac{{ML}^{2}}{12}$