Engineering
Mathematics
Arithmetic Progression and Its Properties
Question

Let a1, a2, a3, ….. be in arithmetic progression of positive terms. Let Ak = a21 – a22 + a23 – a24 +…..+ a22k–1 – a22k If A3 = – 153, A5 = – 435 and a21 + a22 + a23 = 66, then a17 – A7 is equal to_______.

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Solution

Ak = –d[a1 + a2 + a3 +,………+ a2k]
A3 = – 153

2a1+5d=51d..........(1)

A5 = – 435

2a1+9d=87d..........(2)

From (1) & (2)
d = 3
Now, a1
2 + (a1 + d)2 + (a1 + 2d)2 = 66
a12 + (a1 + 3)2 + (a1 + 6)2 = 66
a12 + 6a1 – 7 = 0
(a1 + 7) (a1 – 1) = 0
⇒ a1 = 1
a17 = a1 + 16d = 1 + 16 × 3 = 49
A7 = – 3[7(2 × 1 + 13 × 3)] = – 861
a17 – A7 = 49 + 861 = 910