Let A and B be two independent events such that P \left(\right. A \left.\right) = \frac{1}{3} \textrm{ }\textrm{ } and \textrm{ }\textrm{ } P \left(\right. B \left.\right) = \frac{1}{6}. Then, which of the following is TRUE?

Engineering

Mathematics

Conditional Probability

Question

Let A and B be two independent events such that $P (A) = \frac{1}{3} and P (B) = \frac{1}{6}$ . Then, which of the following is TRUE?

$P (\frac{A'}{B'}) = \frac{1}{3}$

$P (\frac{A}{(A \cup B)}) = \frac{1}{4}$

$P (\frac{A}{B}) = \frac{2}{3}$

$P (\frac{A}{B'}) = \frac{1}{3}$

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A & B are independent events so

$P (\frac{A}{B'}) = \frac{1}{3}$