Engineering
Mathematics
Properties of Definite Integral
Question

Let  f(x) = ln|x+x2+1|. Then  the value of55dx(1+f5(x))+(1+f10(x))dx is

5

25

0

10

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Solution

f(– x) = – f(x)
55(1+f5(x))1+f10(x)(1+f5(x))2(1+f10(x))dx=551+f5(x)1+f10(x)2f5(x)dx=55(12f5+121+f10(x)2f5(x))dx
As  f(x) is an odd function.
(0+1020)=102 = 5.