Match List I with List - II.
|
List – (I) Alkali Metal |
List - (II) Metal Emission Wavelength in nm |
||
| (A) | Li | (I) | 589.2 |
| (B) | Na | (II) | 455.5 |
| (C) | Rb | (III) | 670.8 |
| (D) | Cs | (IV) | 780.0 |
Choose the correct answer from the options given below :
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The reasoning for the correct matching between alkali metals and their emission wavelengths lies in the characteristic emission spectra of these elements. Alkali metals emit light at specific wavelengths when they are heated, and this forms the basis of flame tests. Here's why each pairing is correct:
Lithium (Li) → 670.8 nm:
Lithium ions produce a deep red or crimson flame during the flame test, and its characteristic emission wavelength is around 670.8 nm, which corresponds to red light in the spectrum.
Sodium (Na) → 589.2 nm:
Sodium ions produce a bright yellow flame, and its strongest emission line, the sodium D-line, is at 589.2 nm. This wavelength is associated with yellow light, which is very prominent.
Rubidium (Rb) → 780.0 nm:
Rubidium ions produce a violet flame, and one of its characteristic emission lines is around 780.0 nm. This wavelength is near the infrared region, but still falls within the visible spectrum as a deep red.
Cesium (Cs) → 455.5 nm:
Cesium ions produce a blue or violet flame. The characteristic emission wavelength of cesium is around 455.5 nm, which corresponds to blue-violet light in the visible spectrum.