Engineering
Chemistry
Nucleophilic Substitution

Question

Mechanism for the monochlorination of methane

The reaction of a chlorine radical with an alkane to form a primary, secondary, or tertiary radical is exothermic, the transition states resemble the reactants more than the products. The reactants all have approximately the same energy, so there will be only a small difference in the activation energies for removal of a hydrogen atom from a primary, secondary, or tertiary carbon. In contrast, the reaction of a bromine radical with an alkane is endothermic, so the transition states resemble the products more than the reactants. In other words, because a bromine radical is relatively unreactive, it is very selective about which hydrogen atom it abstracts. In contrast, the much more reactive chlorine radical is much less selective. Reactivity-selectivity principle which states that the greater the reactivity of a species, the less selective it will be.

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Linked Question 1

How many products (including stereoisomers) would you expect to obtain upon mono-chlorination of the indicated substrate under the conditions shown?

3

4

2

5

Solution
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Linked Question 2

Most appropriate transition state structure in chlorination is

Solution
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Free radical having strong combination tendency. 

Linked Question 3

Total number of mono-chloro product (M.C.P.) (including stereoisomer).

Sum of a + b =

6

8

7

9

Solution
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