Moment of inertia of a disc of inner radius a and outer radius b and having mass M about the axis perpendicular to its plane is (A0 ± B0 × 10–2) kg-cm2. Given M = (2 ± 0.02) kg, a = (5 ± 0.05) cm, b = (7 ± 0.07) cm. Find the value of A0 + B0.

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Moment of Inertia

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Moment of inertia of a disc of inner radius a and outer radius b and having mass M about the axis perpendicular to its plane is (A₀ ± B₀ × 10^–2) kg-cm². Given M = (2 ± 0.02) kg, a = (5 ± 0.05) cm, b = (7 ± 0.07) cm. Find the value of A₀ + B₀.

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$I_{2} = \frac{M}{2} (a^{2} + b^{2})$

${ΔI}_{2} = M [aΔa + bΔb] + DM (\frac{a^{2} + b^{2}}{2})$

= A₀ = 74, B₀ = 222