Engineering
Physics
Physical Quantities
Question

Most materials have the refractive index, n > 1. So, when a light ray from air enters a naturally occurring material, then by Shell’s law, sinθ1sinθ2=n2n1 , it is understood that the refracted ray bends towards the normal. But it never emerges on the same side of the normal as the incident ray. According to electromagnetism, the refractive index of the medium is given by the relation, n=(cv)=±εrμr , where c is the speed of electromagnetic waves in vacuum, v its speed in the medium, er and mr are the relative  permittivity and permeability of the medium respectively.

In normal materials, both εr and µr are positive, implying positive n for the medium. When both εr and µr are negative, one must choose the negative root of n. Such negative refractive index materials can now be artificially prepared and are called meta-materials. They exhibit significantly different optical behavior, without violating any physical laws. Since n is negative, it results in a change in the direction of propagation of the refracted light. However, similar to normal materials, the frequency of light remains unchanged upon refraction even in meta-materials.

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Linked Question 1

For light incident from air on a meta-material, the appropriate ray diagram is

Solution
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Since the physical laws remain the same, the speed of light is lesser in meta-materials.

So v = c|n|

1 sin θ1 = n sin θ2. Since n is negative, θ2 is also negative. So the ray rotates and goes on the opposite side of the normal.

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Linked Question 2

Choose the correct statement

The speed of light in the meta-material is v = c

The speed of light in the meta-material is v = c |n|

The wavelength of the light in the meta-material (λm) is given by λm = λair |n|, where λair is the wavelength of the light in air

The speed of light in the meta-material is v=c|n|

Solution
Verified BY
Verified by Zigyan

Since the physical laws remain the same, the speed of light is lesser in meta-materials.

So v = c|n|

1 sin θ1 = n sin θ2. Since n is negative, θ2 is also negative. So the ray rotates and goes on the opposite side of the normal.

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Please subscribe our Youtube channel to unlock this solution.