Number of g- atoms of sulphur present in 80.25 g of sulphur is

Foundation

Chemistry Foundation

Mole Concept and Calculation

Question

Number of g- atoms of sulphur present in 80.25 g of sulphur is - (At. wt. of S = 32)

2.5

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32 g of S contains = 1gram atoms (moles)
80.25 g of S will contain $= \frac{1}{32} \times 80 .25$
= 2.50 g atoms

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