Engineering
Chemistry
Oxidation Number and Calculation
Question
Oxidation number of sulphur in marshall's acid (H2S2O8) is
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Solution
Let x be the oxidation number of sulphur in marshall's acid (H2S2O8). It contains a peroxide linkage. Thus, the oxidation number of two O atoms is –1 and that of the remaining O atoms is –2. The oxidation number of H is +1.
For the neutral molecule, the sum of the oxidation numbers is zero.
Therefore,2 (+1) + 2x + 2(–1) + 6(–2) = 0 or, x = +6
The structure is given below:
